#1883
UEMM
Se dă un șir cu n
elemente, numere naturale. Să se afișeze, pentru fiecare element din șir, valoarea din șir aflată după acesta și mai mare decât acesta. Dacă o asemenea valoare nu există, se va afișa -1
.
Problema | UEMM | Operații I/O | tastatură/ecran |
---|---|---|---|
Limita timp | 0.1 secunde | Limita memorie |
Total: 64 MB
/
Stivă 8 MB
|
Id soluție | #54138312 | Utilizator | |
Fișier | uemm.cpp | Dimensiune | 357 B |
Data încărcării | 20 Noiembrie 2024, 16:53 | Scor / rezultat | Eroare de compilare |
uemm.cpp: In function 'int main()': uemm.cpp:17:13: error: no match for 'operator-' (operand types are 'std::ostream {aka std::basic_ostream<char>}' and 'int') cout-1; ^ uemm.cpp:17:13: note: candidates are: In file included from /usr/include/c++/4.8/bits/stl_algobase.h:67:0, from /usr/include/c++/4.8/bits/char_traits.h:39, from /usr/include/c++/4.8/ios:40, from /usr/include/c++/4.8/ostream:38, from /usr/include/c++/4.8/iostream:39, from uemm.cpp:1: /usr/include/c++/4.8/bits/stl_iterator.h:327:5: note: template<class _Iterator> typename std::reverse_iterator<_Iterator>::difference_type std::operator-(const std::reverse_iterator<_Iterator>&, const std::reverse_iterator<_Iterator>&) operator-(const reverse_iterator<_Iterator>& __x, ^ /usr/include/c++/4.8/bits/stl_iterator.h:327:5: note: template argument deduction/substitution failed: uemm.cpp:17:14: note: 'std::ostream {aka std::basic_ostream<char>}' is not derived from 'const std::reverse_iterator<_Iterator>' cout-1; ^ In file included from /usr/include/c++/4.8/bits/stl_algobase.h:67:0, from /usr/include/c++/4.8/bits/char_traits.h:39, from /usr/include/c++/4.8/ios:40, from /usr/include/c++/4.8/ostream:38, from /usr/include/c++/4.8/iostream:39, from uemm.cpp:1: /usr/include/c++/4.8/bits/stl_iterator.h:379:5: note: template<class _IteratorL, class _IteratorR> decltype ((__y.base() - __x.base())) std::operator-(const std::reverse_iterator<_Iterator>&, const std::reverse_iterator<_IteratorR>&) operator-(const reverse_iterator<_IteratorL>& __x, ^ /usr/include/c++/4.8/bits/stl_iterator.h:379:5: note: template argument deduction/substitution failed: uemm.cpp:17:14: note: 'std::ostream {aka std::basic_ostream<char>}' is not derived from 'const std::reverse_iterator<_Iterator>' cout-1; ^ In file included from /usr/include/c++/4.8/bits/stl_algobase.h:67:0, from /usr/include/c++/4.8/bits/char_traits.h:39, from /usr/include/c++/4.8/ios:40, from /usr/include/c++/4.8/ostream:38, from /usr/include/c++/4.8/iostream:39, from uemm.cpp:1: /usr/include/c++/4.8/bits/stl_iterator.h:1104:5: note: template<class _IteratorL, class _IteratorR> decltype ((__x.base() - __y.base())) std::operator-(const std::move_iterator<_Iterator>&, const std::move_iterator<_IteratorR>&) operator-(const move_iterator<_IteratorL>& __x, ^ /usr/include/c++/4.8/bits/stl_iterator.h:1104:5: note: template argument deduction/substitution failed: uemm.cpp:17:14: note: 'std::ostream {aka std::basic_ostream<char>}' is not derived from 'const std::move_iterator<_Iterator>' cout-1; ^ In file included from /usr/include/c++/4.8/bits/stl_algobase.h:67:0, from /usr/include/c++/4.8/bits/char_traits.h:39, from /usr/include/c++/4.8/ios:40, from /usr/include/c++/4.8/ostream:38, from /usr/include/c++/4.8/iostream:39, from uemm.cpp:1: /usr/include/c++/4.8/bits/stl_iterator.h:1111:5: note: template<class _Iterator> decltype ((__x.base() - __y.base())) std::operator-(const std::move_iterator<_Iterator>&, const std::move_iterator<_Iterator>&) operator-(const move_iterator<_Iterator>& __x, ^ /usr/include/c++/4.8/bits/stl_iterator.h:1111:5: note: template argument deduction/substitution failed: uemm.cpp:17:14: note: 'std::ostream {aka std::basic_ostream<char>}' is not derived from 'const std::move_iterator<_Iterator>' cout-1; ^ uemm.cpp:5:15: warning: unused variable 'maxi' [-Wunused-variable] int n,v[1001],maxi=0,i,j; ^
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema UEMM face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.